(PHP 4 >= 4.0.4, PHP 5, PHP 7)
ctype_digit — Check for numeric character(s)
$text
)
Checks if all of the characters in the provided string,
text
, are numerical.
text
The tested string.
Returns TRUE
if every character in the string
text
is a decimal digit, FALSE
otherwise.
버전 | 설명 |
---|---|
5.1.0 |
Before PHP 5.1.0, this function returned TRUE
when text was an empty string.
|
Example #1 A ctype_digit() example
<?php
$strings = array('1820.20', '10002', 'wsl!12');
foreach ($strings as $testcase) {
if (ctype_digit($testcase)) {
echo "The string $testcase consists of all digits.\n";
} else {
echo "The string $testcase does not consist of all digits.\n";
}
}
?>
위 예제의 출력:
The string 1820.20 does not consist of all digits. The string 10002 consists of all digits. The string wsl!12 does not consist of all digits.
Example #2 A ctype_digit() example comparing strings with integers
<?php
$numeric_string = '42';
$integer = 42;
ctype_digit($numeric_string); // true
ctype_digit($integer); // false (ASCII 42 is the * character)
is_numeric($numeric_string); // true
is_numeric($integer); // true
?>
Note:
This function expects a string to be useful, so for example passing in an integer may not return the expected result. However, also note that HTML forms will result in numeric strings and not integers. See also the types section of the manual.
Note:
-128이상 255이하의 integer를 지정할 경우, 한 문자의 ASCII 값으로 해석합니다. (음수는 256이 더해져 확장 ASCII 영역의 문자가 됩니다) 그 외의 정수는 그 정수를 표현하는 10진 문자열로 해석합니다.